z^2+(5-2i)*z+5-5=0i

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Solution for z^2+(5-2i)*z+5-5=0i equation:


Simplifying
z2 + (5 + -2i) * z + 5 + -5 = 0i

Reorder the terms for easier multiplication:
z2 + z(5 + -2i) + 5 + -5 = 0i
z2 + (5 * z + -2i * z) + 5 + -5 = 0i

Reorder the terms:
z2 + (-2iz + 5z) + 5 + -5 = 0i
z2 + (-2iz + 5z) + 5 + -5 = 0i

Reorder the terms:
5 + -5 + -2iz + 5z + z2 = 0i

Combine like terms: 5 + -5 = 0
0 + -2iz + 5z + z2 = 0i
-2iz + 5z + z2 = 0i

Anything times zero is zero.
-2iz + 5z + z2 = 0i

Solving
-2iz + 5z + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-5z' to each side of the equation.
-2iz + 5z + -5z + z2 = 0 + -5z

Combine like terms: 5z + -5z = 0
-2iz + 0 + z2 = 0 + -5z
-2iz + z2 = 0 + -5z
Remove the zero:
-2iz + z2 = -5z

Add '-1z2' to each side of the equation.
-2iz + z2 + -1z2 = -5z + -1z2

Combine like terms: z2 + -1z2 = 0
-2iz + 0 = -5z + -1z2
-2iz = -5z + -1z2

Divide each side by '-2z'.
i = 2.5 + 0.5z

Simplifying
i = 2.5 + 0.5z

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